If |y-1/2|<11/2, which of the following could

Mohammad Aasim

I do not know how you guys got the right answer. It must be a nice method but here is how i made it to the right answer;

Looking at the inequality makes one thing prominent that value of y must keep the LHS (left hand side) smaller than the RHS (right hand side). Secondly, LHS, after simplication, would yield an absolute value with POSITIVE sign.

Ignore the intergers (whether positive or negative) in the options at your first sight because they would only make the numerator bigger. (You may notice that the denominator on both sides are going to be the same i.e. 2, after simplification)

Left with option B and C that bear fractions, you can configure that option B would again make the numerator equal to +12 (absolute value), resultantly making the LHS bigger than RHS. So, option B is out.

We are left with the 'OPTION C' only. (The explanation may seem lengthy, but is probably less vulnerable to time consumption, at least that is what i thought.)

Aug 10, 2017 • Comment

Ajosh John

|y-1/2| < 11/2

convert into decimals

|y-0.5| < 5.5

now subsitute

a) |-11-0.5| = |-11.5| = 11.5, hence 11.5>5.5

b) |-11/2-0.5| = |-5.5-0.5| = |-6| = 6, hence 6> 5.5

c) |5.5-0.5| = |5| = 5, hence 5 < 5.5 which is the answer.

Dec 18, 2015 • Comment

Robert M Oliver

Is there a more simple way to come up with this answer?

Nov 16, 2015 • Comment

Mike McGarry, Magoosh Tutor

Dec 26, 2013 • Comment