Running at the same constant rate, 6

Christoph Mader

I came to (B) with an estimation, I'm not quite sure though if it is a 100% correct but the easiest way would be:

6 Machines -> 270 bottles / min
12 Machines -> 540 bottles / min

in 4 minutes -> 540*4 = 2160

So (C), (D), (E) are out of question already
(A) is out of question as well because 270*4 > 648, so 4 Machines would already produce more then 648.

Only suitable answer -> (B)

Aug 25, 2019 • Comment

Joseph R Ross

Used the mental math concept of "estimation" explained in the intro to math videos, since the answers were spread apart.
1. Rounded up 270 to 300, which is easily divided by 6. So roughly one machine can produce 50 bottles per minute.
2. 10 machines * 50 bottles = 500 bottles per min.
3. 500 bottles per min * 4 mins. = roughly 2000 bottles
4. Taking into account the rounding up in beginning, the closest answer is 1800 bottles.

May 9, 2016 • Comment

MOHIT TYAGI

In 1 min: 270/6=x/10 (x is no of bottles by 10machines)
x=450 bottles per min x 4mins= 1800btls

May 14, 2014 • Comment

Mike McGarry, Magoosh Tutor

Dec 27, 2013 • Comment