An object thrown directly upward is at

An object thrown directly upward is at a height of h feet after t seconds, where h=-16(t-3)+150. At what height, in feet, is the object 2 seconds after it reaches its maximum height

3 Explanations

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Sean Gregory

Can you please explain why h(5) is there instead of the original formula of h? If I followed how you solved it at the end you would be left with h(5)=86, then you would need to divide 86/5, H=17.2

Mar 12, 2015 • Comment

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Omar shaaban

The New York Mets need to hire you as the Moneyball of the organization. Great job explaining things, Mike!

Dec 14, 2014 • Comment

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Mike McGarry, Magoosh Tutor