Skip to Main Content

Source: Official Guide for GMAT Review 2016 Problem Solving; #86

▲

2

For a party, three solid cheese balls with

For a party, three solid cheese balls with diameters of 2 inches, 4 inches, and 6 inches, respectively, were combined to form a single cheese ball. What was the approximate diameter, in inches, of the new cheese ball? (The volume of a sphere is 4/3?r^3, where r is the radius.)

1 Explanation

▲

1

Lee Pierce

Combining the 3 cheese balls you get 4/3 pi (1+8+27) = 48 pi

48 pi = 4/3 pi r^3

- divide both sides by 4/3 pi

36 = r^3
d =2 * (cubed root of 36)

Answer = E

Aug 17, 2016 • Comment

Sam Kinsman

Yes, good job! :D

Aug 19, 2016 • Reply

Add Your Explanation

You must have a Magoosh account in order to leave an explanation.

Learn More About Magoosh

Official GMAT Material

Official Guide for GMAT Review 2016

Official Guide for the GMAT 2015 14th Ed.

Official Guide for the GMAT 13th Ed.

Nova's GRE Prep

Official Guide for the GMAT 12th Ed.

Revised GRE PDF 2nd Ed.

Section 5.3 Problem Solving

Improve Your Score

Magoosh GMAT is an affordable online course for studying the GMAT.

Learn More About Magoosh

Share Post

Return to Forum