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Source: Official Guide for GMAT Review 2016 Problem Solving; #86

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2

For a party, three solid cheese balls with

For a party, three solid cheese balls with diameters of 2 inches, 4 inches, and 6 inches, respectively, were combined to form a single cheese ball. What was the approximate diameter, in inches, of the new cheese ball? (The volume of a sphere is 4/3?r^3, where r is the radius.)

1 Explanation

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1

Lee Pierce

Combining the 3 cheese balls you get 4/3 pi (1+8+27) = 48 pi

48 pi = 4/3 pi r^3

- divide both sides by 4/3 pi

36 = r^3
d =2 * (cubed root of 36)

Answer = E

Aug 17, 2016 • Comment

Sam Kinsman

Yes, good job! :D

Aug 19, 2016 • Reply

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