If x and y are positive integers, what is the value of x + y?
2 Explanations
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1
John Robertson
Used test cases, SQR(X)+SQR(Y)=?
1) x+y = 15, could be for x & y, 10 and 5, 9 and 4, etc. Can't get a lock on what x and y are, IS
2) SQR(xy)=6. Indicates xy=36, as only solution for that perfect square to =6 is SQR(36).
But, you can get for xy: 6x6, 9x4, 12x3, etc.
IS
1&2) knowing x+y=15, and SQR(xy)=6, 12+3=15, satisfies (1), and 12x3=36, satisfies (2). Without solving for SQR(x)+SQR(y), you know x and y are definitely 12 and 3 in either order, and it could be solved out.
S, (D)
Recognise that squaring the original (X^0.5 + Y^0.5?)^2 leads to X + 2(XY)^0.5 + Y. Knowing the value of the latter is one step away from answering the question.
1: X + Y = 15
In X + 2(xy)^0.5 + Y, this statement does not answer the value of 2(XY)^0.5
Insufficient
2: (XY)^0.5 = 6
In X + 2(XY)^0.5 + Y, this statement does not answer the value of X + Y
Insufficient
1 & 2: Using both statements we can solve X + 2(XY)^0.5 + Y
-> 15 + 2*(6) = 27
-> X^0.5 + Y^0.5 = 27^0.5 = (3*9)^0.5 = 3 * (3)^0.5
2 Explanations