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If k is an odd integer, which of the following must be an even integer?
Title
Which must be even
Your Result
Correct
Difficulty
Medium
Your Pace
0:02
Others' Pace
1:09
Video Explanation
Text Explanation
The easiest way to solve this is to pick a value for k, and then plug into each of the answer choices. The easiest odd integer to use is 1, so let's plug in k = 1:
A: k2 – 4 --> (1)2 − 4 = −3
B: 3k + 2 --> 3(1) + 2 = 5
C: 2k + 1 --> 2(1) + 1 = 3
D: --> =
E: --> = 2
The only one that gives us an even integer is E, so (E) is our answer.
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